21 cm
42 cm
42cm
(Hint: a +
+
2 2
42 = 21... Side of the square = 21 cm.)
14. Find the area of the shaded region in each of the following figures:
Answers
⇒ Here, Radius of circle r=7cm
⇒ Area of circle =πr
2
=
7
22
×(7)
2
=154cm
2
⇒ Side of equilateral triangle is 14cm.
⇒ Area of equilateral triangle =
4
3
×(side)
2 ⇒ Area of equilateral triangle =
4
3
×(14)
2
⇒ Area of equilateral triangle =
4
1.73
×196=84.87cm
2
⇒ ∠A=60
o
[ Angle of equilateral triangle ]
∴ θ=60
o
⇒ Area of sector =
360
o
θ
×πr
2
⇒ Area of sector =
360
o
60
o
×
7
22
×(7)
2
∴ Area of sector =25.66cm
2
⇒ Area of shaded region = (Area of circle + Area of equilateral triangle ) - 2×Area of sector
⇒ Area of shaded region =(154+84.87)−51.32=187.55cm
2
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