21. Crystal of copper sulphate was dropped in beaker "A" containing hot water and beaker "B" containing
cold water. Both the beakers were left undisturbed for fifteen minutes. Now answer the following questions:
(a) What will be the color of water in both the beakers after fifteen minutes?
(b) In which beaker water will become colored at the earliest? Why?
(c) Which characteristic of matter is exhibited in the given activity?
Answers
Answer:
{a} He must have observed that the crystal of copper sulphate in beaker A has diffused evenly than in beaker B. This describes the phenomenon of diffusion. On heating, diffusion becomes faster because the kinetic energy increases. So the particles of CuSO4(copper sulphate) must have diffused with the particles of hot water quickly than in the cold water.
{b} THE COLOUR OF SOLUTION IN FIRST BEAKER BECOMES BLUE SLOWLY WHERE AS THE COLOUR BECOMES BLUE FASTER IN SECOND BEAKER. THE RATE OF DIFFUSION INCREASES WITH INCREASE IN TEMPERATURE BECAUSE KINETIC ENERGY OF MOLECULES. AS TEMPERATURE INCREASES PARTICLES MOVE FASTER SO MIXING OF CRYSTALS IS FASTER IN HOT WATER..
{c} The zig-zag movement of small particles suspended in a liquid or a gads is called Brownian motion.Brownian motion tells us that the particles are tiny nature and the particles of a matter are constantly moving. a) Particles of matter have spaces between them. b) Particles of matter are in continuous motion.
Explanation:
Answer:
Explanation:
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