Chemistry, asked by himanshu77754, 1 year ago

21. Determine the radius of fifth Bohr orbital of
hydrogen atom.
22. Find out the amount of energy emitted when an
electron jumps from an orbital with n=3 to n=
2.(E=1.9 eV)
23. What will be the angular
momentum of an
electron in the fifth Bohr's energy level?
24. An object of 20 Kg is moving with a velocity of
100 ms and its de Broglie's wavelength is 6.62
x 10 m. Find the value of x.(0.1 kg)
25. Uncertainty of momentum, for an electron is 1
x 10 kg, then find the uncertainty in its
position (x=5.27 x 10 m).​

Answers

Answered by nagathegenius
0

Answer:

Explanation:

apply the formula of radius of orbit

radius of orbit formula

n^2*h^2*epsilon/m*pie*atomic number*charge of electron^2

put n=5

you will get

2)apply 1/lamda=rz^2(1/n1-1/n2)

here we dont you lamda

so we should calculate individual energy

and subtract energies to get energy emission

3)angular momentum of electron

is always root 3/ 2 *h/2pie

4)use formula

delta x*delta p=h/4pie

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