Question

21. Find the largest four-digit number which when divided by 4, 7 and 13
leaves a remainder of 3 in each case.
​

Answer 1

Answer:

Prime factors of 4,7 and 13

4=2×2

7 and 13 are prime numbers 

LCM  (4,7,13)=36

we know that, the largest 4 digit number is 9999.

Step 1 : divide 9999 by 364, we get 

9999 ÷ 364 =171 

Step 2: subtract 171 from 9999 

9999−171=9828

Since a remainder of 3 is to be left 

9282+3=9831 

therefore 9831 is the number.

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