Question

21. Find the least number which when divided by
(a) 20, 24 and 32 leaves 5 as remainder
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Answer 1

I hope this helps

Solution : The least number which is exactly divisible by 20 , 24 and 36 is the LCM of these numbers . We first to find the LCM of 20 , 24 and 32

LCM = 2 × 2 × 2 × 2 × 2 × 3 × 5 = 480

But the required number is number that leaves remainder of 5 in each case.

That means the required number is 5 more than the LCM required number is equal 480 - 5 = 475

Answer = 475