Question

21] Find the molarity of solution it 90 g of glucose (C6H12O6) is dissolue in 200 ML Solution.​

Answer 1

Explanation:

Molarity is measured in units of mol/L.

So, we must divide the number of moles of glucose by the total volume of solution in L.

Converting grams of glucose to moles requires the molar mass (M) of glucose (180.156 g/mol)

n = m/M = 90.0 g/180.156 g/mol = 0.4996 mol

Molar concentration can now be determined by dividing moles by volume (in L or dm3).

25.0 cm3 = 25.0 mL = 0.0250 L (or 0.0250 dm3)

C = n/V = 0.4996 mol/0.0250 L = 19.98 mol/L = 20.0 M (to 3 significant digits

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