Question

21. Find the number of solutions of the pair of equations 6x - 3y + 10 = 0 and 2x - y + 9 = 0​

Answer 1

Step-by-step explanation:

the linear the linear equations are

6 x-3 Y + 10 =0

2x-y+9=0

6x-3y=-10

2x-y=-9

here, a1=6, b1=-3, c=-10

a2=2, b2=-1, c2=-9

a1/a2 = 6/2=3

b1/b2 =-3/-1 =3

c1/c2= -10/-9=10/9

a1/a2+ b1/b2≠c1/c2

hence,proved