Question

21. Find the sum
of the question

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Answer 1

hope it helps you｡◕‿◕｡

Answer 2

ANS:

(121a-66b)/(a-b)

Step-by-step explanation:

given that dinominator is same for every term then the denominator is same for ans also.

As denominator is same then the numerator terms add directly.

i.e..

1. For rhe numerator we can see that the 'a' terms are in AP with common difference 2.

then sum of n terms which are in ap

n/2(2a+(n-1)d)

11/2(2*1+(11-1)*2)=121.

similarly for b terms also in ap with common difference 1. then sum of n terms in ap

11/2*(2*1+(11-1)*1)=66.

then we get the final ans is

(121a-66b)/(a+b).

thankyou.