Question

21. Find Value of x for figure given
20
ND
(x+20)
(x+3)
(x+7)
E
B​

Answer 1

Answer:

Let us assume, DAE = x

Triangle ABC is isosceles as AB=BC−−>BCA=CAB=x

Hence, CBD=CAB+BCA=x+x=2x.............. [External angle of triangle ABC]

Triangle BCD is isosceles as BC=CD−−>CBD=CDB=2x

Hence, DCE=DAE+CDA=x+2x=3x.............. [External angle of triangle ACD]

Triangle CDE is isosceles as CD=DE−−>DCE=DEC=AED=3x

Similarly, ADE=EFD=AEF+DAE=EGF+DAE=(DAE+GFA)+DAE=DAE+DAE+DAE=3x

Hence, in triangle ADE,ADE+DAE+AED=3x+x+3x=7x

Hence, 7x=180−−−>x=180/7

stay home stay safe ❤️