Physics, asked by ram821126, 8 months ago

21. For the chemical equilibrium A + 2B 2C, the value of the equilibrium constant, K, is 10. What is the value of the
equilibrium constant for the reaction written in reverse?
K-972
2CA + 2B
K=10
Given that: A+2B2C
a. 0.10
b. 10
c. 1
d. 100
e. -10​

Answers

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0

Answer:

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