Question

(
21. From the velocity-time plot shown in figure, find
(a)distance travelled by the particle during the first 40 seconds.
(b)displacement travelled by the particle during the first 40 seconds
5 m/s
O
20
40 tesi
5 m/s
​

Answer 1

Answer:

Step 1: Distance calculation

The area under the velocity-time graph is displacement.

Here upward area is positive and downward area is negative. But for distance we will take both area as positive because distance is always positive.

Distance in first 40 sec is ΔOAB+ΔBCD

D=

2

1

×20×5+

∣

∣

∣

∣

∣

−

2

1

×20×5

∣

∣

∣

∣

∣

m (Distance is always positive)

=100m

Step 2: Average velocity calculation

Average velocity =

time

Total Displacement

Displacement =50m+(−50m)=0

∴ Average velocity =0

Hence distance travelled during first 40s is 100m and average velocity is 0.

Explanation:

Hope it helps you ⟵(o_O)