Question

21) Give the values of x and y in reaction Be2C +xH:0 → y Be(OH)2 + CH.
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Answer 1

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The correct value of x is 4, and y is (OH)2 ...

Then the correct eqn is

Be2C + 4 H2O = 2 Be(OH)2 + CH4. 

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hope this is !

Answer 2

Answer:

In the reaction Be2C + xH2O - yBe(OH)2+ CH4 the value of x and y are. X = 4 and y =2 by using law of conservation of mass.