Chemistry, asked by reshmiraj5june, 11 months ago

21. Hydrogen peroxide in solution decomposes to give water and oxygen gas. From the
following data show that decomposition of H2O2 in aqueous solution is a first-order
reaction.
time (min) 0,15,30

Vol (mL) of KMnO4 25.4 ,9.83, 3.81

The volume of standard KMnO4 is given for titrating the same volume of the reac-
tion mixture.​

Answers

Answered by anuashugoodluck
0

Answer:

Given that decomposition of H

2

O

2

in aqueous solution follows first order kinetics.

For first order reactions,

K=

t

1

ln

[A]

t

[A]

0

where, K is the rate constant,

t= time

[A]

0

= Initial concentration of reactant (i.e. H

2

O

2

)

[A]

t

= concentration of reactant at t=t

Now, concentration of H

2

O

2

present at any time is proportional to volume of KMnO

4

used in titration.

Now, given that

at, t=0; volume of KMnO

4

used=22.8mL∝[A]

At t=600s;Volume of KMnO

4

used=13.8mL∝[A]

t

So, K=

600

1

ln(

13.8

22.8

)

⇒K=

600

1

×0.5=0.00084s

−1

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