Question

21. If 1/a = x/(y + z). 1/b = y(x + z) and 1/c = zl(x + y)
and x + y + z #0, then 2/(a + 1) + 2/(b+1) + 2/(c + 1)
(A) 1 (B) 1/2 02 (D) 6
is​

Answer 1

Answer:

Step-by-step explanation:

Put value of a, b,c get ans in 2 step

Answer 2

Answer:

2

Step-by-step explanation:

take the values of a,b,c from the give data and simply substitute