Question

21. If 2x - 10°, x + 10° and 3x are the measures of the angles of A POR
respectively, then the smallest angle is​

Answer 1

Answer:

2x -10+x+10+3x = 180

6x = 180

x = 30

angle = 50,40,90

smallest angle = 40

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Answer 2

solutions,

Given,

In a ∆POR,

measure of first angle = 2x -10°

measure of second angle =x + 10°

measure of third angle = 3x

To find,

smallest angle=?

A/q,

=> 2x -10° + x +10° +3x = 180°(by angle sum property)

=> 2x +x +3x = 180° - 10° +10°

=> 6x = 180°

=> x = 180°/6

=> x = 30°

Now,

measure of the first angle = 2x-10 = 2×30-10= 50°

measure of the second angle= x + 10 = 30+10 = 40°

measure of the third angle = 3x = 3 × 30 = 90°

second angle is the smallest angle of the ∆POR which is 40°

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