21. If a 50 and then find 2 + b 2 + c 2 = 2 ab + bc + ca = 3, a + b + c
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2
Answer:
२०१८ — If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the ... [c^2+a^2, 1, (c+a+2 )^2]| : (A) abc(a^2 + b^2 +c^2) (B) 0 (C) a^3+b^3+c^3 + 3abc ... · या पानाचे भाषांतर करा
Answered by
1
Answer:
Using the identity is (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
It is given that a
2
+b
2
+c
2
=50 and ab+bc+ca=47, therefore,
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
=a
2
+b
2
+c
2
+2(ab+bc+ca)
=50+(2×47)
=50+94=144
⇒(a+b+c)
2
=144
⇒a+b+c=−
144
,
144
⇒a+b+c=−12,12
Hence, the value of (a+b+c) is −12 or 12.
Step-by-step explanation:
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