Question

21. If sec 0 = 18, find sin 0 and cot 0.
12​

Answer 1

Answer:

let 0 be X.

secX=18(given)

cosX=1/secX

cosX=1/18

cotX=cosX/sinX

cotX=1/18/sinX

cotX=sinX/18

sinX=18cotX

now, find sinX and cotX

Answer 2

Answer:

Sec0=18/1 =h/b

Therefore, (18)^2 -(1)^2 = 324 -1

= 323 = under root 323

Sin0= 18/under root 323

Cot0= 1 /under root 323

(Remember that underroot is a sign )