Question

21) If sin theta =3/5 then find the value of tan² theta+cot²theta? your answer is right I will mark at brainlist​

Answer 1

Answer:

$\sin( \alpha ) = \frac{3}{5} = \frac{perpendicular}{hypotenuse}$

Let hypo. = 5 units and perpendicular = 3 units.

Then, By Pythagoras theorem,

${5}^{2} = {3}^{2} + {base}^{2}$

$= > {base}^{2} = 25 - 9 = 16$

$= > base = \sqrt{16} = 4 \: units$

Therefore,

$\tan( \alpha ) = \frac{3}{4} and \: \cot( \alpha ) = \frac{4}{3}$

Now,

${ \tan}^{2} \alpha + { \cot }^{2} \alpha = { (\frac{3}{4}) }^{2} + { (\frac{4}{3} )}^{2} = \frac{9}{16} + \frac{16}{9}$

$= \frac{81 + 256}{144} = \frac{337}{144}$

I Hope that it is correct.

Answer 2

Answer:

oye u said na give please thanks