Question

21) If sum of two numbers is 1638 and their HCF is 91, then the possible number of pairs of such numbers are
a) 2
B)3
C) 4
D) 5​

Answer 1

Answer:

B) 3

Step-by-step explanation:

x + y = 1638

HCF is 91

Therefore, 91x + 91y = 1638

=> x + y = 18

So,

There are 3 such possible pairs of nos. whose sum is 18 :

1+17 = 18

5+13 = 18

&

7+11 = 18

These are the only possible pairs since they don't have any common factor.