Question

21. If the area of an isosceles right triangle is 8 cm^2, what is the perimeter of the triangle?
Solve using heron's formula !!!​

Answer 1

Step-by-step explanation:

In right isosceles ∆ABC Area of triangle = 1 2 12(Base x Altitude) 8 = 1 2 12(x x x) = 1 2 x 2 12x2 x = √ 16 16 = 4 cm (AC)2 = (AB)2 + (BC)2 y2 = x2 + x2 y2 = 42 + 42 y2 = √ 4 2 + 4 2 42+42 = √ 32 32 = 4 √ 2 2 cm Perimeter of ∆ABC = AB + BC + CA = 4 + 4 + 4 √ 2 42= 8 + 4 √ 2 42 cm