Question

21) If the distance of , from the points (3, 6) and −3, 4 are equal, prove that

3 + = 5 [2]

OR

If the points ​

Answer 1

Answer:

Good Morning.....

Distance formula =

$\sqrt{ {x2 - x1}^{2} + {y2 - y1}^{2} }$

A(3,6)

B(-3,4)

C(x,y)

By problem ,

AC = BC

√(x-3)² + (y-6)² = √(x-(-3)² + (y-4)²

√x²+9-6x + (y²+36-12y) = √x²+9+6x + (y²+16-8y)

√x²-6x+9+y²-12y+36 = √x²+6x+9+y²-8y+16

(Square roots get cancelled)

x²-6x+9+y²-12y+36 = x²+6x+9+y²-8y+16

(x² and y² gets cancelled)

-6x+9-12y+36 = 6x+9-8y+16

9-9-12y-8y = 6x+6x

-20y = 12x

4(-5y) = 4(3x)

(4 gets cancelled)

-5y = 3x

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