21. In a village, a bird is sitting on the top of a tree, which is 80 m high. The angle of elevation
of the hand, from a point on the ground is 45. The bird flies away from the point of
observation horizontally and remains at a constant height After 2 seconds, the angle of
clevation of the bird from the point of observation becomes the complementary angle of
60
Based on the above information, answer the following questions: (Attempt any four)
(1) Draw the correct figure based on the above information.
(n) Find the angle of elevanon of the bird after 2 second.
(w)Find the distance covered by bird after 2 seconds.
(iv) Find the speed of flying of the bird.
(v) If the height is doubled, then what will be the new distance covered by the bird.
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Answer:
tan45
o= BCAC
1= BC80
BC=80cm
tan30 o= BC+CE
DE=31
= 80+x80
80+x=80
3x=80
3−80
x=80( 3 −1)m
The bird travelled 80( 3−1)m
Speed of bird = Time
Distance= 240( 3−1)
=40( 3 −1)m/s
∴ Speed =40( 3 −1)m/s,
Step-by-step explanation:
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