Question

21. In figure, BE || CD, angle DCG = 85°, angle EBF = 10°
and AC = BC. Find angle FAC and angle ACB.​Pls can anyone solve this

Answer 1

Answer:

angleFAC=100degrees

ACB=80degrees

Answer 2

Answer:

FAC = 105°

ACB=30°

Step-by-step explanation:

DCG = EBC (BE || CD)

10° + ABC = 85°

ABC = 85° - 10°

ABC = 75°

AC = BC (GIVEN )

ABC = BAC (SIDES THAT ARE EQUAL AND OPPOSITE TO EACH OTHER HAVE OPPOSITE ANGLES EQUAL.)

ABC = CAB = 75°

ACB + ABC + CAB = 180° ( ANGLE SUM PROP. TRIANGLE)

ACB + 75 + 75 = 180

ACB = 180-150

ACB = 30°

FAC + CAB =180° (LINEAR PAIR)

FAC + 75 = 180

FAC = 180-75

FAC =105°