Question

21 In the adjoining figure, D and E are mid-points of the
sides BC and CA respectively of a AABC, right angled
at C. Prove that:
(iii) 4(AD2 + BE2) = 5AB2.​

Answer 1

Answer:

Step-by-step explanation:

here is pic

sorry if iam wrong

Answer 2

There must be two parts of the question before this part right? In order to prove the third part we need the equations formed in the first two parts. On adding those we'll get a single equation and on simplifying it when you replace AC^2 + BC^2 in the last step with AB^2 using Pythagoras theorem from the figure you'll get the desired equation. I hope I helped!!!