21. In the given figure, 2b-a = 65° and ZBOC = 90°, find the measure of ZAOB, ZAOD and ZCOD. с B 2a+b+15 А 26°
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Answer:
ZAOB = 50°
ZAOD = 70°
ZCOD = 150°
Step-by-step explanation:
Sum of all the angles around point O will be 360°
.. ZAOB + ZBOC + <COD + 2DOA = 360°
⇒ a + 90° + (2a + b + 15°) + 2b = 360°
→ 3a + 3b = 360° - 105°
⇒ a + b = 85°
Also given
2a - b = 65°
Adding eq (1) and eq (2)
3a = 150°
⇒ a = 50°
Putting the value of a in eq (1)
we get b = 35°
Therefore
ZAOB = a = 50°
ZAOD = 2b = 2 x 35° = 70°
ZCOD = 2a + b + 15° = 2 x 50° + 35° +15° =
150°
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