Question

21. Ipsit's father is 28 years younger than Ipsit's grandfather and 23 years older than
Ipsit. The sum of the ages of all the three is 110 years. What is the age of each of
them?
99
Tahan ibotod for​

Answer 1

Answer:

Let age of Baichung's father age be x years

∴ Baichung's age and his grandfather's age ⇒(x−29) and (x+26) yrs respectively.

As per the question, Sum of ages of 3 people =135 years

∴x+x−29+x+26=135

3x−3=135

Transpose 3 to RHS, we will get,

3x=138

Divides both sides by 3, we will get

x=

3

138

⇒x=46

Baichung's father age =x=46 years

Baichung's age =x−29=46−29=17 years

Baichung's grandfather's age =x+26=46+26=72 years

Answer 2

Explanation:

Ipsit = 38

ipsit father age=35+28=53

ipsit grandfather age= 35-23