Question

21. खगोलीय दूरदर्शक की आवर्धन क्षमता के लिए व्यंजक प्राप्त करें। Find out the expression for magnifying power of an Astronomical telesco​

Answer 1

ok so I don't know if you have any questions please feel welcome....

Explanation:

ok so I can

Answer 2

The expression for magnifying power of an Astronomical Telesco​.

• A telescope is indeed an optical apparatus that is being used to see distant objects such as a star, a planet, or a faraway tree, among other things. This telescope's magnification power is reported as  $\frac{-f_{o} }{f_{e} }$ .
• And when both the object and the projection are at eternity, the length of the telescope in standard adjustment is given by $f_{u} + f_{e}$ =L.

    where m is the telescope's magnification power, $f_{o}$ is the objective's focal length, $f_{e}$ is the eyepiece's focal length, and L is the telescope's usual adjustment length.

• An astronomical telescope is a highly reflective telescope that is used to see celestial bodies including planets, stars, and satellites. It is comprised of two diverging lenses that are coaxially positioned on the exterior ends of two sliding tubes.
• When both photos & objects are all infinitely, magnifying power is determined as the percentage of the angle surrounded there at eye either by the final picture as seen from the telescope towards the degree subtended there at the eye by that of the object viewed directly.