21. Prove that:
Cos4x + Cos3x + Cos2x
Sin4x + Sin3x + Sin2x
= Cot 3x
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Step-by-step explanation:
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Step-by-step explanation:
cos4x+cos3x+cos2x)/(sin4x+sin3x+sin2x)=cotx
LHS
=(cos4x+cos2x+cos3x)/(sin4x+sin2x+sin3x)
=[2cos3x.cosx+cos3x]/[2sin3x.cosx+sin3x]
=[cos3x(2cosx+1)]/[sin3x(2cosx+1)]
=cos3x/sin3x
=cot3x , proved
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