Question

21
Q.15. A burner raises the temperature of 500 g of
water from 10°C to 100°C in 5 minutes. What
heat is supplied per second? (Ans. 630 Js-1)​

Answer 1

Answer:

Power = 627 J/s

Explanation:

Q = mcΔT

Where:

Q is the heat (energy)

m is mass of water = 500g

c is the specific heat of water (constant) = 4.18 J/g°C

ΔT is the change in temperature = 100 - 10 = 90 °C

we know that Power = Energy/time

so Energy Q = P×t

P×t = mcΔT      or       P =mcΔT/t

t = 5 minutes = 5×60 = 300 s

P = 500×4.18×90/ 300

  = 627 J/s