21. Raj is an electrician ina village. One day power was not there in entire village and villagerscalled Raj to repair the fault. After thorough inspection he found an electrie fault in one of theelectric pole of height 5 m and he has to repair it. He needs to reach a point 1m below the topof the pole to undertake the repair work. What should be the length of the ladder that she shoulduse which, when inclined at an angle of a such that cota =tan(210' - 3a) to the horizontal,would enable his to reach the required position? Also, how far from the foot of the pole shouldhe place the foot of the ladder? (Use 3 - 1.73)
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Ladder Height = 4.613 m , Distance from the foot of the pole =2.307 m
Step-by-step explanation:
Cota = Tan(210° - 3a)
=> Tan (90° - a) = Tan (210° - 3a)
=> 90° - a = 210° - 3a
=> 2a = 120°
=> a = 60°
Tan 60° = ( 5 - 1)/ Distance from the foot of the pole
=> √3 = 4/Distance from the foot of the pole
=> Distance from the foot of the pole = 4/√3
= 4√3/3
= 4 * 1.73/3
= 2.307 m
Sin60° = (5 - 1)/Ladder Height
=> √3 / 2 = 4/Ladder Height
=> Ladder Height = 8/√3
=> Ladder Height = 4.613 m
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