Question

21. Solve x^2-2x+3=0 by using the quadratic formula.​

Answer 1

Step-by-step explanation:

Given :-

x^2-2x+3=0

To find:-

Solve x^2-2x+3=0 by using the quadratic formula.

Solution:-

Given equation is x^2 -2x +3 = 0

On comparing with the standard quadratic equation ax^2+bx+c = 0

then we have

a= 1

b=-2

c=3

We know the quadratic formula to find the roots for the given quadratic equation ax^2+bx+c =0

x=[ -b±√(b^2 - 4ac)]/2a

On Substituting the values in the formula then

=>X = [-(-2)±√{(-2)^2 -4(1)(3)}]/2(1)

=>X = [2±√(4-12)]/2

=>X = [2±√-8]/2

=>X= [2±√(4×-2)]/2

=>X= [2±2√-2]/2

=>X=2(1±√-2)/2

=>X=1±√-2

X= 1+√-2 and 1-√-2

Answer:-

The roots of the given equation are 1+√-2 and 1-√-2

Used formula:-

• the quadratic formula to find the roots for the given quadratic equation ax^2+bx+c =0

x=[ -b±√(b^2 - 4ac)]/2a

• Quadratic formula is derived by the Indian mathematician Sridharacharya .It is known as Sridharacharya formula.

Answer 2

Answer:

x = 1 + √-2 or x = 1 - √-2

HOPE IT HELPS YOUU!!!