Question

21. The ionization potentials of
Li and K are 5.4 and 4.3 eV
respectively. The ionization
potential of Na will be:
(1) 9.7 eV
(2) 1.1 eV
(3) 4.9 eV
(4) Cannot be calculated​

Answer 1

Answer:

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• Ionization Potential of Na = 4.9 eV

$\huge \underline \bold \red {But Why ?}$

• Ionization Potential of an atom is the amount of energy required to remove an electron from a neutral isolated gaseous atom.
• It leads to formation of a cation

$\huge\boxed{\fcolorbox{green} </u></strong><strong><u>{</u></strong><strong><u>blue</u></strong><strong><u>}{</u></strong><strong><u>✍</u></strong><strong><u>}}$Variations In Ionization Potential:

• Ionization Potential decreases as we move down a group because of decerse of atom size
• Ionization Potential increases as we across a period from left to right because of increase in nuclear charge which counteracts increase in size.

Thus Along The period 1

Li ♤

Na |

K |

Thus Li has most Ionization potent in Group 1 .

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Hope it helps

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