Question

21. The mean of the data set (4,10,7,7,6,9,3,8,9) is
22. The median of the above data set is​

Answer 1

Given :

• Data set (4,10,7,7,6,9,3,8,9)

Find :

• Mean
• Median

Solution :

Lets find out mean first.

Formula for Mean -

$\boxed{\bf{Mean = \dfrac{\Sigma x_{i}}{n}}}$

Here,

$\bf{\Sigma x_{i}}$ = Sum of given observation

$\bf{n}$ = Total number of observations.

Putting up the values, we get :

$:\implies \bf{Mean = \dfrac{\Sigma x_{i}}{n}}$

$:\implies \bf{Mean = \dfrac{4+ 10 + 7 + 7 + 6 + 9 + 3 + 8 + 9}{9}}$

$:\implies \bf{Mean = \dfrac{63}{9}}$

$:\implies \bf{Mean = 7}$

$\boxed{\therefore \sf{Mean = 7}}$

Now , For Median

As we see the number of Observations or are odd.

$\boxed{\sf{Median = \dfrac{(n+1)}{2}}}$

Putting up the values, we get :

$\implies\sf {Median = \dfrac{n+1}{2}}$

$\implies\sf {Median = \dfrac{9+1}{2}}$

$\implies\sf {Median = \dfrac{10}{2}}$

$:\implies \bf{Median = 5th \: Term}$

Let's arrange the given data set in arranging order now ,

3, 4 , 6, 7, 7, 8, 9, 9, 10.

Now, The 5th term is " 7 "

$\boxed{\therefore \sf{Median = 7}}$