Question

21. The sum of the digits of a 2 digit number is 9. 27 added to this number is

the same as the number obtained by interchanging the digits of the original

number. Find the number.​

Answer 1

Answer:

Hence the two digit no. is = 10(9-x)+x = 10 (9-6) +6 10*3+6=30+6 =36

Step-by-step explanation:

Hope it helps you

Answer 2

Answer :

36

Solution :

Let the tens digit and the once digit be x and y respectively .

Then ,

Original number = 10x + y

Also ,

On interchanging the digits , the tens digit and the once digit of the new number will be y and x respectively .

Thus ,

New number = 10y + x

Now ,

According to the question , 27 added to the original number is the same as the number obtained by interchanging its digits .

Thus ,

=> 10x + y + 27 = 10y + x

=> 10x - x + y - 10y = -27

=> 9x - 9y = -27

=> 9(x - y) = -27

=> x - y = -27/9

=> x - y = -3 -------(1)

Also ,

It is given that , the sum of digits of the required number is 9 .

Thus ,

=> x + y = 9 ---------(2)

Now ,

Adding eq-(1) and (2) , we get ;

=> x - y + x + y = -3 + 9

=> 2x = 6

=> x = 6/2

=> x = 3

Now ,

Putting x = 3 in eq-(2) , we get ;

=> x + y = 9

=> 3 + y = 9

=> y = 9 - 3

=> y = 6

Hence ,

Required number is 36 .