Question

21. The weight in grams of a non-volatile solute
(mol. wt. 60) to be dissolved in 90 g of water to
produce a relative lowering of vapour pressure
of 0.02 is
plz help guys
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Answer 1

Answer:

6g is the right answer.

Explanation:

Refer attachment for explanation!!!

Answer 2

Answer:

The weight if non volatile solute is 6gm

Explanation:

Given that,

Molecular weight of non volatile solute=60

Weight of water=90gm

Relative lowering of vapour pressure=0.02

Relative lowering of vapour pressure is given by relation,

$RLVP= \frac{w \times M}{m \times W}$

Where,

w=Weight of non volatile solute.

M=Molecular weight of water.

m=Molecular weight of non volatile solute.

W=Weight of water.

Substituting these values,we get

$0.02 = \frac{w \times 18}{60 \times 90} \\ = > w = 6gm$

Therefore,the weight if non volatile solute is 6gm

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