21 Two crossroads, each of width 10 m, cut at right angles through the centre of a
rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area
of the roads Also find the area of the park excluding cross roads. Give the answer in
hectares
Answers
Answer:
giving you answer of the little bit same question
Step-by-step explanation:
Here, PQ=10m and PS=300m, EH=10m and EF=700m
And KL=10m and KN=10m
Area of roads = Area of PQRS+Area of EFGH−Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
=PS×PQ+EF×EH−KL×KN
=(300×10)+(700×10)−(10×10)
=3000+7000−100
=9,900m
2
Area of road in hectares, 1m
2
=
10000
1
hectares
∴9,900m
2
=
10000
9900
=0.99 hectares
Now, Area of park excluding cross roads = Area of park−Area of road
=(AB×AD)−9,900
=(700×300)−9,900
=2,10,000−9,900
=2,00,100 m
2
=
10000
200100
hectares=20.01 hectares.Here, PQ=10m and PS=300m, EH=10m and EF=700m
And KL=10m and KN=10m
Area of roads = Area of PQRS+Area of EFGH−Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
=PS×PQ+EF×EH−KL×KN
=(300×10)+(700×10)−(10×10)
=3000+7000−100
=9,900m
2
Area of road in hectares, 1m
2
=
10000
1
hectares
∴9,900m
2
=
10000
9900
=0.99 hectares
Now, Area of park excluding cross roads = Area of park−Area of road
=(AB×AD)−9,900
=(700×300)−9,900
=2,10,000−9,900
=2,00,100 m
2
=
10000
200100
hectares=20.01 hectares.