Question

21. Two electric bulbs, each designed
to operate with a power of 500 W
in 220 V lines are put in series in
a 110 V. What will be the power
generated by each bulb?
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Answer 1

thanos rhanis thanos thanos tha.nos

Answer 2

Resistance R=V²/power =48400/500=96.8 homs

Now net resistance when connected in series will be 96.8+963.6 homes

so now power =net voltage/ net resistance=

110/193.6=62.5 watt so power by each bulb

will be just half of it i.e., 31.25 watt