Question

21. Two pieces of plane glass are placed
together with a piece of paper between the two
at one edge. On viewing the air fillim normally
with monochromatic light of wavelength 6000
Å, 20 bands are observed in one om. Find the
angle of the wedge
ints)​

Answer 1

Explanation:

we have OA = 10 cm and AB = 0.04 mm so that .so two-glass-plates-enclose-wedge-shaped-air-film-touching-at-one-edge-and-are-separated-wire

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Answer 2

Answer: The wedge angle between the two pieces of glass is equal to (120000 Å) / (2 x d).

Explanation: The wedge angle between two pieces of glass can be calculated using the equation:

Angle of wedge = (nλ) / (2d cos θ)

Where n is the number of bands observed, λ is the wavelength of light used, d is the thickness of the paper between the two pieces of glass, and θ is the angle of incidence of the light on the wedge.

In this case, n = 20, λ = 6000 Å, d = unknown, and θ = 90°.

We can rearrange the equation to solve for d:

d = (nλ) / (2cosθ angle of wedge)

Substituting our values, we get:

d = (20 x 6000 Å) / (2 x cos90° x angle of wedge)

d = (120000 Å) / (2 x angle of wedge)

Next, we can rearrange the equation to solve for the angle of wedge:

Angle of wedge = (120000 Å) / (2d)

Substituting our values, we get:

Angle of wedge = (120000 Å) / (2 x d)

Therefore, the wedge angle between the two pieces of glass is equal to (120000 Å) / (2 x d), where d is the thickness of the paper between the two pieces of glass.

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