Math, asked by shubham6747, 9 months ago

21. What is the argument of the complex number (-1-i),
where i = √-1?

(b) – 5π÷4
(a) 5π÷4
(C) 3π÷4
(d) None of these​

Answers

Answered by riteshritx1
1

Answer:

Step-by-step explanation:

Question 1:

Express the given complex number in the form a + ib: (5i)(-3i/5)

Answer:

(5i)(-3i/5) = (-5 * 3/5) * I * i

                  = -3 * i2

                  = -3 * (-1)                  [Since i2 = -1]

                  = 3

Question 2:

Express the given complex number in the form a + ib: i9 + i19

Answer:

i9 + i19 = i4*2 + 1 + i4*4 + 3

           = (i4)2 * i + (i4)4 * i3

           = (1)2 * i + (1)4 * i * i2                 [Since i4 = 1]

           = i + i * (-1)                                  [Since i2 = -1]

           = i – i

           = 0

Question 3:

Express the given complex number in the form a + ib: i-39

Answer:

i-39 = i-4 * 9 - 3

    = (i-4)9 * i-3

    = (1/i4)9 * i-3

   = 19 * i-3                     [Since i4 = 1]

   = i-3

   = 1/ i3

   = i4/ i3                        [Since i4 = 1]

   = i

Question 4:

Express the given complex number in the form a + ib:  3(7 + i7) + i(7 + i7)

Answer:

Given, 3(7 + i7) + i(7 + i7) = 21 + 21i + 7i + 7i2

                                             = 21 + 21i + 7i - 7            [Since i2 = -1]

                                             = 14 + 28i

Question 5:

Express the given complex number in the form a + ib: (1 – i) – (–1 + i6)

Answer:

Given, (1 – i) – (–1 + i6) = 1 – i + 1 - 6i

                                         = 2 - 7i    

Question 6:

Express the given complex number in the form a + ib: (1/5 + 2i/5) – (4 + 5i/2)

Answer:

Given, (1/5 + 2i/5) – (4 + 5i/2) = 1/5 + 2i/5 – 4 - 5i/2

                                                     = (1/5 - 4) + (2i/5 - 5i/2)

                                                     = -19/5 + (4i - 25i)/10    

                                                     = -19/5 - 21i/10      

Question 7:

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