Question

21. What number has to be added to each term of 4: 7 to make the ratio 5:6?
O 13
O 12
O 10
O 11​

Answer 1

Answer:

11

Step-by-step explanation:

Let x shouod be added to each term to make the ratio 5:6.

=> (4 + x)/(7 + x) = 5/6

=> 6(4 + x) = 5(7 + x)

=> 24 + 6x = 35 + 5x

=> 6x - 5x = 35 - 24

=> x = 11

11 has to be added to each term of 4: 7 to make the ratio 5:6

Answer 2

Answer:

Given :-

• A each term of 4 : 7 to make the ratio 5 : 6.

To Find :-

• What is the number.

Solution :-

Let, the number to be added be y

According to the question :

↦ $\sf \dfrac{4 + x}{7 + x} =\: \dfrac{5}{6}$

By doing cross multiplication we get,

↦ $\sf 6(4 + x) =\: 5(7 + x)$

↦ $\sf 24 + 6x =\: 35 + 5x$

↦ $\sf 6x - 5x =\: 35 - 24$

➠ $\sf\bold{\red{x =\: 11}}$

$\therefore$ 11 should be added to each term of 4 : 7 to make the ratio 5 : 6.