21. When an object is placed at a distance of 60 cm from a diverging spherical mirror, the magnification
produced is 0.5. Where should the object be placed to get a magnification of 1/3 ?
Answers
Given that,
Object distance u = –60 cm
then
⇒ V = 30 cm.
Now use mirror formula to find its focal length (f)
Again from question:-
Let object distance = –x
Then by using the mirror formula
Hence the required object distance = 120 cm
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OTHER ANSWERS
Gopal Menon
Gopal Menon, B Tech Chemical Engineering, Indian Institute of Technology, Bombay (1975)
Answered Feb 15, 2018 · Author has 4.2k answers and 2m answer views
Originally Answered: When an object is placed at a distance of 60 cm from a convex mirror, the magnification produced is 1/2, where should the object be placed to get a magnification of 1/3?
The mirror formula is 1v+1u=1f,1v+1u=1f, where,
uu is the distance of the object from the mirror,
vv is the distance of the image from the mirror, and,
ff is the focal length.
The distance from the mirror to the left is taken as negative and the distance from the mirror to the right is taken as positive.
The magnification is =hiho=−vu,=hiho=−vu, where,
hihi is the height of the image, and,
hoho is the height of the object.
The distance above the principal axis is taken as positive and the distance below the principal axis is taken as negative.
In a convex mirror, uu is always negative and ff is always positive.
In a convex mirror the image is always virtu...
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Aakanksha Kote
Aakanksha Kote, studied at Oakridge International School
Answered Dec 4, 2017
Given,
U=-30cm, m=1/2
Using the formula m= -v/u
½= -v/-30
V=+15cm.
Using the mirror formula,
1/f=1/v+1/u
1/f= 1/15+1/-30
F=+30 cm.
Again m’ =-v’/u’
1/3 =-v’/u’
V’ =-u’/3
Using again, 1/f= 1/v’+1/u’
1/30=-3/u’+1/u’
1/30= -2/u’
U’=-60cm.
Hence the object should be placed at a distance of 60cm infront of a convex mirror to get a magnification of 1/3.
same way do it for 60 cm according to your question
:)