Question

. 21-x(2x+1)+2(xー4) (x+2)=0.​

Answer 1

Answer:

Here's your answer

$21 - 2 {x}^{2} - x + 2x - 8(x + 2) = 0 \\ \\ 21 - 2 {x}^{2} + x - 8x - 16 = 0 \\ \\ - 2 {x}^{2} - 7x + 5 = 0 \\ \\ 0 = 2 {x}^{2} - 7x + 5$

$2 {x}^{2} - 7x + 5 \\ \\ 2 {x}^{2} - 2x - 5x + 5 \\ \\ 2x(x - 1) - 5(x - 1) \\ \\ (x - 1)(2x - 5)$

Hope it helps ✌✌.....