Math, asked by pathakswapna476, 20 days ago

21 x² = 4 (2x+1)
(quadratic equations)​

Answers

Answered by jsyadav69
0

Answer:

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Step-by-step explanation:

21 x² = 4 (2x+1)

21x²= 8x +4

21x²-8x-4=0

21x²-(14-6)x-4=0

21x²-14x+6x-4=0

x(21x-14)+2(3x-2)=0

21x-14=0 x+2=0

x=14/21 x=-2

Answered by suhanirana2007
1

Answer:

x = 2/3

x = - (2/7)

Step-by-step explanation:

21x^2 = 8x + 4

21x^2 - 8x - 4 = 0

21x^2 + 6x - 14x - 4 = 0

(21x^2 + 6x) + (-14x - 4) = 0

3x(7x + 2) - 2(7x + 2) = 0

(3x - 2)(7x + 2) = 0

3x - 2 = 0

7x + 2 = 0

x = 2/3

x = -(2/7)

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