21 y square + 4 Y - 12 is equal to zero
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Answered by
1
21y² + 4y - 12 = 0
21y² + 18y - 14y - 12 = 0
3y(7y + 6) - 2(7y + 6) = 0
(7y + 6) (3y - 2) = 0
y = - 6/7 or y = 2/3
21y² + 18y - 14y - 12 = 0
3y(7y + 6) - 2(7y + 6) = 0
(7y + 6) (3y - 2) = 0
y = - 6/7 or y = 2/3
Answered by
1
We have ,
21y² + 4y - 12 = 0
By quadratic formula
y = -4 ± √16 + 1008/ 42
y = -4 ± √1024/ 42
y = -4 ± 32 /42
on taking positive sign
y = -4 + 32/42 = 28/42 = 2/3
on taking negative sign
y = -4 - 32/42
y = -36/42 = -6/7
Y = 2/3 or -6/7
21y² + 4y - 12 = 0
By quadratic formula
y = -4 ± √16 + 1008/ 42
y = -4 ± √1024/ 42
y = -4 ± 32 /42
on taking positive sign
y = -4 + 32/42 = 28/42 = 2/3
on taking negative sign
y = -4 - 32/42
y = -36/42 = -6/7
Y = 2/3 or -6/7
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