Question

210 g of Mno, on reaction with HCl forms 2.24 L of Cl (9) at NTP, the percentage impurity of MnCl, is
Mno, + 4HCI MnCl, + Cl2 + 2H,0
(
1876
2 25% na rua​

Answer 1

Answer:

13%

Explanation:

Here, as per the given equation, 1 mole of Cl

2

is formed from 1 mole of MnO

2

Therefore,

Number of moles of Cl

2

is n=

22.4L

2.24L

=0.1 mol

Therefore, Mass of Cl

2

is given by W=87g/mol×0.1 mol=8.7 g

Impurity in MnO

2

=10g−8.7g=1.3g

Percentage impurity=

10g

1.3g

×100=13%

Hence, the correct option is D