Question

.2¹¹÷2⁵=2-³×2²n-¹

find n

help me please​​

Answer 1

Answer:

Step-by-step explanation:

2^11÷2^5= 2^-3× 2^2n-1

law= a^m÷a^n= a^m-n

a^m×a^n= a^m+n

2^(11-5)= 2^(-3+2n-1)

2^6= 2^ -4+2n

base is same so power becomes same.

6= -4+2n

10=2n

n= 10/2

n= 5.

Step-by-step explanation:

Answer 2

Answer:

2^11÷2^5= 2^-3× 2^2n-1

law= a^m÷a^n= a^m-n

a^m×a^n= a^m+n

2^(11-5)= 2^(-3+2n-1)

2^6= 2^ -4+2n

Base is same so power becomes same.

6= -4+2n

10=2n

n= 10/2

n= 5.

Step-by-step explanation:

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