Question

211 = 4,Z2= 4, then 1Z1 + Z2 + 3
+ 4ij is less than?​

Answer 1

211= 4 , Z2= 4 , = 211 / 4×Z2=4

= 52.75×Z2=4

= 52.75×{Z=4/2}

=52.75×{ Z = 2}

=52.75×2

=105.5

1Z1+Z2+3+4ij= 1×Z×1+Z×2+3+4×i×j

=({1×1}=1)1×2+3+4×i×J

=. 9×i×j

= ij= 9

105.5-9 is less than= 96.5

answer is 96.5

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