Question

213. Velocity of a particle increases from 10m/s to 15m/s after travelling a distance of 5m its
cceleration is
N
12.5m/s?
b) 125 m/s?
S
c) 1.25m/s?
d) 0.1m/s?​

Answer 1

Answer:12.5 m/s

Explanation:Use the third equation for motion

Which is :-

V^2 - U^2 = 2as

Where V is final velocity =15m/a

U is initial velocity = 10m/a

S is the distance covered = 5m

A is to be found out

Therefore

V^2 - U^2 = 2as

15^2 - 10^2 = 2 × a × s

225-100= 10a

125 = 10a

a = 125/10

a = 12.5 m/s^2

Answer 2

Answer:

(A) is correct answer 12.5m/s