Question

(216+1) (216-1) ( 7×223) (296+1) which one is a whole number

Answer 1

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(296 + 1 ) is correct ✔
solution is below here
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Let X = 232x

Than , ( 232 + 1 ) = ( x + 1 )

Here , ( x + 1 ) be completely divisible by the N ( natural number )

Than ,
$\: \: \: \: \: \: (296 + 1) \\ = >[ (232)3 + 1 ]= ( {x}^{3} + \: 1) \\ = > (x + 1)( {x}^{2} - x + 1)$
It is completely divisible by natural number,
since ( x +1 ) = (296 + 1 ) is divisible by natural number (N)

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