Question

√216– 5√6 + √294 - (3 / √6)
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Answer 1

Answer:

18.3711731

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Answer 2

Question -

Simplify -

$\sf \: \sqrt{216} - 5 \sqrt{6} + \sqrt{294} - \frac{3}{ \sqrt{6} }$

Answer:

$= \tt\sqrt{216} - 5 \sqrt{6} + \sqrt{294} - \dfrac{3}{ \sqrt{6} }$

$= \tt\sqrt{216} - 5 \sqrt{6} + \sqrt{294} - \dfrac{3 \sqrt{6} }{6}$

$= \tt \dfrac{6 \sqrt{216} - 30 \sqrt{6} + \sqrt{294} - 3 \sqrt{6} }{6}$

$= \tt\dfrac{6 \sqrt{6 \times 6 \times 6 \times } - 30 \sqrt{6} - 3 \sqrt{6} + 6 \sqrt{2 \times 3 \times 7 \times 7} }{6}$

$= \tt \dfrac{6 \sqrt{ {6}^{2} \times 6} - 33 \sqrt{6} + 6 \sqrt{2 \times 3 \times {7}^{2} } }{6}$

$= \tt\dfrac{6 \times 6 \sqrt{6} - 33 \sqrt{6} + 6 \times 7 \sqrt{6} }{6}$

$= \tt\dfrac{36 \sqrt{6} - 33 \sqrt{6} + 42 \sqrt{6} }{6}$

$= \tt\dfrac{78 \sqrt{6} - 33 \sqrt{6} }{6}$

$= \tt \dfrac{45 \sqrt{6} }{6}$